On 01.01.2010, at 23:56, Hugo Duncan wrote:
>> I want to create a new instance of a deftype from inside one of its
>> methods.
>
> I ended-up using extend-type for this case.
That's probably the cleanest solution, but you lose the performance
benefit of defining methods right in the type definition.
After looking at the deftype code, I came up with the following
solution:
(defprotocol Foo
(foo [x]))
(deftype Bar
[i]
Foo
(foo [] (new Bar (inc i))))
(foo (Bar 0))
Its drawback is relying on an undocumented feature: the value of Foo
inside the methods is the class Foo being defined.
Konrad.
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