Hi,
On Oct 14, 4:42 pm, Mark Tomko <[email protected]> wrote:
> (defn count-matching-elements [coll1 coll2]
> (reduce +
> (for [e1 coll1 e2 coll2]
> (if (= e1 e2) 1 0))))
Please note, that this probably is not what you meant:
(for [x [1 2]
y [4 5]]
(vector x y))
=> ([1 4] [1 5] [2 4] [2 5])
You can remove items from the list with :when.
(for [x [1 2]
y [4 5] :when (odd? (+ x y))]
(vector x y))
=> ([1 4] [2 5])
Your original question can be done with for also:
(defn matching-elements-x
[s1 s2]
(for [[e1 e2] (partition 2 (interleave s1 s2)) :when (= e1 e2)]
e1))
Sincerely
Meikel
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