On Mar 24, 2009, at 15:44, Mark Volkmann wrote:
> I'm wondering if there is a way to avoid that using a macro. The hard
> part is printing the expression. The following doesn't work. It
> outputs "3 = 3".
>
> (defmacro dump2 [expr]
> `(let [value# ~expr]
> (pr ~expr)
> (println " =" value#)))
> (dump2 (+ 1 2))
All it takes to make it work is a slight modification:
(defmacro dump [expr]
`(let [value# ~expr]
(pr (quote ~expr))
(println " =" value#)))
(dump (+ 1 2))
prints:
(+ 1 2) = 3
Konrad.
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