On 09/08/2019 15:00, Matthew Fernandez wrote:
On Aug 9, 2019, at 05:23, Chris Hall via cfe-users wrote:
I find that __builtin_constant_p() works as expected, but
__has_builtin(constant_p) denies it !
I believe you need __has_builtin(__builtin_constant_p).
Ah :-( So you do... sorry... I have no idea why I thought otherwise :-(
Similarly __builtin_expect() and __builtin_types_compatible_p() !
Except that __has_builtin(__builtin_types_compatible_p) also denies it.
#include <stdio.h>
int
main(int argc, char* argv[])
{
printf("__has_builtin(__builtin_types_compatible_p)=%d\n"
"__builtin_types_compatible_p(int, int)=%d\n"
"__builtin_types_compatible_p(int, long)=%d\n",
__has_builtin(__builtin_types_compatible_p),
__builtin_types_compatible_p(int, int),
__builtin_types_compatible_p(int, long)) ;
}
outputs:
__has_builtin(__builtin_types_compatible_p)=0
__builtin_types_compatible_p(int, int)=1
__builtin_types_compatible_p(int, long)=0
I hope I haven't missed something blindingly obvious this time.
Thanks,
Chris
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