rsmith added a comment.
Thanks, I think this can be simplified a bit but this looks like the right fix.
================
Comment at: lib/Sema/SemaDecl.cpp:12609-12610
return false;
+ // We can't simply call Type::isUndeducedType here, because it returns
+ // false on C++14's auto return type without trailing return type.
+ DeducedType *DT = FD->getReturnType()->getContainedDeducedType();
----------------
I don't think this comment captures the problem. Rather, I think the problem is
that in a template we deduce the `auto` to a dependent type, so it's not
considered "undeduced" at the point when we ask this question.
================
Comment at: lib/Sema/SemaDecl.cpp:12612-12613
+ DeducedType *DT = FD->getReturnType()->getContainedDeducedType();
+ if (DT && DT->getDeducedType().isNull())
+ return false;
+ }
----------------
Is there any need to check whether the type has been deduced here? It seems
simpler (and equivalent) to turn off skipping for functions whose return type
involves a deduced type regardless of whether deduction has been performed
already (which it hasn't).
Repository:
rC Clang
https://reviews.llvm.org/D44480
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