djasper added a comment. I think doing the computation twice is fine. Or at least, I'd need a test case where it actually shows substantial overhead before doing what you are doing here. Understand that creating more States and making the State object itself larger also has cost and that cost occurs in the combinatorial exploration of the solution space. Doing an additional computation at the end should be comparatively cheap. Look at it this way: During the exploration of the solution space, we might enter breakProtrudingToken many times for the same comment. One more time during reconstruction of the solution is not that harmful.
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