On Fri, Apr 21, 2017 at 4:03 AM, Hal Finkel via Phabricator < revi...@reviews.llvm.org> wrote:
> hfinkel added a comment. > > In https://reviews.llvm.org/D32199#732737, @rsmith wrote: > > > In https://reviews.llvm.org/D32199#732189, @hfinkel wrote: > > > > > In https://reviews.llvm.org/D32199#731472, @rsmith wrote: > > > > > > > 1. C's "effective type" rule allows writes to set the type pretty > much unconditionally, unless the storage is for a variable with a declared > type > > > > > > > > > To come back to this point: We don't really implement these rules now, > and it is not clear that we will. The problem here is that, if we take the > specification literally, then we can't use our current TBAA at all. The > problem is that if we have: > > > > > > write x, !tbaa "int" > > > read x, !tbaa "int" > > > write x, !tbaa "float" > > > > > > > > > TBAA will currently tell us that the "float" write aliases with > neither the preceding read nor the preceding write. > > > > > > Right, C's TBAA rules do not (in general) permit a store to be reordered > before a memory operation of a different type, they only allow loads to be > moved before stores. (Put another way, they do not tell you that pointers > point to distinct memory locations, just that a stored value cannot be > observed by a load of a different type.) You get the more general "distinct > memory locations" result only for objects of a declared type. > > > > C++ is similar, except that (because object lifetimes do not currently > begin magically due to a store) you /can/ reorder stores past a memory > operation of a different type if you know no object's lifetime began in > between. (But currently we do not record all lifetime events in IR, so we > can't do that today. Also, we may be about to lose the property that you > can statically determine a small number of places that might start an > object lifetime.) > > > > > Also, a strict reading of C's access rules seems to rule out the > premise underlying our struct-path TBAA entirely. So long as I'm accessing > a value using a struct that has some member, including recursively, with > that type, then it's fine. The matching of the relative offsets is a > sufficient, but not necessary, condition for well-defined access. C++ has > essentially the same language (and, thus, potentially the same problem). > > > > I agree this rule is garbage, but it's not as permissive as I think > you're suggesting. The rule says that you can use an lvalue of struct type > to access memory of struct field type. In C this happens during struct > assignment, for instance. It does *not* permit using an lvalue of struct > field type to access unrelated fields of the same struct. So C appears to > allow this nonsense: > > > > char *p = malloc(8); > > *(int*)p = 0; > > *(int*)(p + 4) = 0; > > struct S {int n; float f;} s = *(struct S*)p; // use lvalue of type > `struct S` to access object of effective type `int`, to initialize a `float` > > > > > > but not this nonsense: > > > > float q = ((struct S*)p)->f; // ub, cannot use lvalue of type `float` > to access object of effective type `int` > > > > > > ... which just means that we can't make much use of TBAA when emitting > struct copies in C. > > > > In C++, on the other hand, the rule is even more garbage, since there is > no way to perform a memory access with a glvalue of class type. (The > closest you get is that a defaulted union construction/assignment copies > the object representation, but that's expressed in terms of copying a > sequence of unsigned chars, and in any case those are member functions and > so already require an object of the correct type to exist.) See > wg21.link/cwg2051 > > > Our struct-path TBAA does the following: > > struct X { int a, b; }; > X x { 50, 100 }; > X *o = (X*) (((int*) &x) + 1); > > int a_is_b = o->a; // This is UB (or so we say)? > This is UB. A good resource for this stuff is http://www.cl.cam.ac.uk/~pes20/cerberus/ which has a long document where they exlpore all of these and what various compilers do, along with what the standard seems to say.
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