mizvekov added a comment.
In D131351#3718725 <https://reviews.llvm.org/D131351#3718725>, @aaron.ballman
wrote:
> However, we don't care about the type mismatch when doing a redeclaration or
> when dropping the attribute, as in:
>
> __attribute__((noreturn)) void my_exit(void);
> void (*handler)(void) = my_exit; // Silently drops the attribute
>
> _Noreturn void my_exit(void) { // No concerns about the type mismatch on
> redeclaration because we inherit __attribute__((noreturn))
> }
>
> so maybe we shouldn't worry about it here.
Are you sure? If the function types don't match in C++, I would expect that to
become a different overload, not a redeclaration, right?
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