mprobst added inline comments. ================ Comment at: lib/Format/TokenAnnotator.cpp:2128 @@ +2127,3 @@ + if (Right.is(tok::exclaim) && (Left.isOneOf(tok::identifier, tok::r_paren, + tok::r_square, tok::r_brace) || + Left.Tok.isLiteral())) ---------------- Tests added. A literal cannot really be null, but the operator is allowed after any kind of expression, and it's straight forward to test for it here.
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