rjmccall added inline comments.

================
Comment at: lib/Sema/SemaType.cpp:7421
+      // - template specialization as addr space in template argument doesn't
+      //   affect specialization.
+      (T->isDependentType() && (!T->isPointerType() && !T->isReferenceType() &&
----------------
Anastasia wrote:
> rjmccall wrote:
> > I don't understand what you're saying here.  Why does inference depend on 
> > whether the type is a template specialization?  And what does this have to 
> > do with template arguments?  Also, address spaces in template arguments are 
> > definitely part of the template argument and affect which specialization 
> > you're naming.
> What I am trying to say here is that an address space of a template argument 
> isn't used as an address space of a template specialization and therefore we 
> can deduce the address space of a template specialization since it's not 
> going to be provided during the template instantiation.
> 
> Let's say we have specialization `MyClass<T>`. The address space of `T` has 
> nothing to do with the address space of `MyClass<T>`. They are different. 
> Therefore if the address space of `MyClass<T>` is not provided explicitly it 
> is ok to deduce it.
> 
> Does it make sense?
Of course the address space of `T` has nothing to do with the address space of 
`MyClass<T>`, but that's true of literally every type, and you don't need to 
add special cases checking for specific type spellings.

Why don't you just never infer address spaces on dependent types and then infer 
them as necessary during instantiation?  Why is it important to infer address 
spaces on any dependent type in the template pattern?


CHANGES SINCE LAST ACTION
  https://reviews.llvm.org/D64400/new/

https://reviews.llvm.org/D64400



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