Update of bug #51414 (project make):
Status: None => Not A Bug
Open/Closed: Open => Closed
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Follow-up Comment #1:
Actually what's happening is that your rule is being misinterpreted as a
static pattern rule, not a pattern rule, and it's not because you are using
$$%, it's because you are using a substitution reference in a secondary
expansion. Also it doesn't matter how many uses of "$$%" you use; even one
substitution reference will show this problem.
Because you have used "$$" in the prerequisites list, make doesn't interpret
this as a variable reference. That means the open parenthesis is not part of
a variable reference and has no special meaning to make. So when make sees
this:
blahblah : $$(%:blah)
it tokenizes this string as "blahblah", ":", "$$(%", ":", "blah)". The ":" IS
a special character to make, it's a rule separator. When make sees a word
containing the special character "%" between two ":" characters it interprets
this to be a static pattern rule. Because the "target" doesn't match the
pattern, you get this error.
I don't see any way to solve this problem: the grammar here is simply
ambiguous and make can't know what you mean.
In order to do what you want you cannot use a substitution reference
(directly) because of the ":" character in it. You can either use a patsubst
function:
.SECONDEXPANSION:
libmy.a(my_source.o): $$(patsubst %_source.o,%,$$%)_internal.h
(here there's no ":" in the prereq list so it works). Or you can use a
variable to hide the ":" and ensure that make parses things correctly:
nosource = $$(%:_source.o=)
.SECONDEXPANSION:
libmy.a(my_source.o): $$(nosource)_internal.h
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