# This messsage can be executed by make to illustrate my problem. all: ; @$(call f,a,b)
# The details of macro argument processing aren't clear to me, so I'm # asking. It appears that all macro arguments are optional, for # instance: define g $1 $2 endef # The macro g can be called with any number of arguments, e.g., # "$(call g,a)" or "$(call g,a,b,c)". Extra arguments are never # expanded/substituted and missing arguments have an empty value. Is # this correct? # If the above is correct, then I experience an issue when macros call # other macros. For instance, here "f" takes two arguments, but # passes only one of them to "g" omitting the second argument. define f # Use $1 somehow... echo $(call g,$2) endef # Here lies the issue. Even though "g" receives only one argument, # "$2" still has the value from "f". I expect this makefile to print # simply "b", but it prints "b b". Is this correct? # If I add a comma like this "$(call g,$2,)" (providing an empty # second argument) the code works as expected. -- Robert _______________________________________________ Bug-make mailing list [EMAIL PROTECTED] http://mail.gnu.org/mailman/listinfo/bug-make
