%% jie zhang <[EMAIL PROTECTED]> writes: jz> I wrote two shell scripts, jz> while1:while echo -n;do echo while1;done jz> while2:while echo -n;do echo while2;done jz> and a Makefile,like this jz> test: jz> . while1;\ jz> . while2 jz> Then I run 'make -j 2',when I use 'ps -e' to view jz> active process,I found two 'sh' process.I think I jz> should only see one 'sh' process,because I use ';' to jz> split two command.Why I saw two process?
Whether you put these together with backslash/newline or not, they will never be run in parallel. Make never runs multiple command lines in the same target build script in parallel; that would be disastrous. I can't say what's going on in your case: I tried what you did and I saw only one shell invoked, just as you'd expect: psmith 8852 8851 73 00:18 pts/2 00:00:01 /bin/sh -c . while1; . while2 Maybe the other shell you're seeing is doing something else, or from a previous invocation that's still running. -- ------------------------------------------------------------------------------- Paul D. Smith <[EMAIL PROTECTED]> Find some GNU make tips at: http://www.gnu.org http://www.paulandlesley.org/gmake/ "Please remain calm...I may be mad, but I am a professional." --Mad Scientist _______________________________________________ Bug-make mailing list [EMAIL PROTECTED] http://mail.gnu.org/mailman/listinfo/bug-make
