Justus Winter, le Fri 06 Jun 2014 16:42:10 +0200, a écrit :
> * include/refcount.h (refcounts_promote): Use ~0U.
> (refcounts_demote): Likewise.
Ack.
> ---
> include/refcount.h | 4 ++--
> 1 file changed, 2 insertions(+), 2 deletions(-)
>
> diff --git a/include/refcount.h b/include/refcount.h
> index 5c3302d..785b052 100644
> --- a/include/refcount.h
> +++ b/include/refcount.h
> @@ -160,7 +160,7 @@ refcounts_promote (refcounts_t *ref, struct references
> *result)
> So we just add a hard reference. In combination, this is the
> desired operation. */
> const union _references op =
> - { .references = { .weak = ~0, .hard = 1} };
> + { .references = { .weak = ~0U, .hard = 1} };
> union _references r;
> r.value = __atomic_add_fetch (&ref->value, op.value, __ATOMIC_RELAXED);
> assert (r.references.hard != UINT32_MAX || !"refcount overflowed!");
> @@ -188,7 +188,7 @@ refcounts_demote (refcounts_t *ref, struct references
> *result)
> significant bits. When we add ~0 to the hard references, it will
> overflow into the weak references. This is the desired
> operation. */
> - const union _references op = { .references = { .hard = ~0 } };
> + const union _references op = { .references = { .hard = ~0U } };
> union _references r;
> r.value = __atomic_add_fetch (&ref->value, op.value, __ATOMIC_RELAXED);
> assert (r.references.hard != UINT32_MAX || !"refcount underflowed!");
> --
> 2.0.0.rc2
>
--
Samuel
> Quelqu'un aurait-il une solution pour réinitialiser un MBR
Si tu veux qu'il soit complètement blanc (pas souhaitable, à mon avis) :
dd if=/dev/zero of=/dev/hda bs=512 count=1 (sous Linux)
-+- OT in Guide du linuxien (très) pervers - "Pour les K difficiles" -+-
