https://sourceware.org/bugzilla/show_bug.cgi?id=24286
Bug ID: 24286
Summary: Can't relocate protected-visibility reference against
a --defsym'd definition
Product: binutils
Version: 2.33 (HEAD)
Status: UNCONFIRMED
Severity: normal
Priority: P2
Component: gold
Assignee: ccoutant at gmail dot com
Reporter: srk31 at srcf dot ucam.org
CC: ian at airs dot com
Target Milestone: ---
Created attachment 11658
--> https://sourceware.org/bugzilla/attachment.cgi?id=11658&action=edit
Test case
If I have an undefined symbol with protected visibility, I get an internal
gold error when attempting to relocate a reference to that symbol when
its definition is provided via --defsym. Example:
foo.c:
int foo(void)
{
return 42;
}
uses-blah.c:
extern int blah(void) __attribute__((visibility("protected")));
int bar(void)
{
return blah();
}
$ make foo.o uses-blah.o
...
$ cc -shared -o /dev/null uses-blah.o foo.o \
-Wl,--defsym,blah=foo \
-Wl,-fuse-ld=gold
The BFD linker happily processes this. But gold (as of git revision
cd5a152cebb201e98f3dbeca510aa39e838a1f62) bombs:
/usr/local/bin/ld.gold: internal error in relocate, at x86_64.cc:4802
collect2: error: ld returned 1 exit status
The failing assertion at x86_64.cc:4802 is this.
case elfcpp::R_X86_64_PLT32:
case elfcpp::R_X86_64_PLT32_BND:
gold_assert(gsym == NULL
|| gsym->has_plt_offset()
|| gsym->final_value_is_known()
|| (gsym->is_defined()
&& !gsym->is_from_dynobj()
&& !gsym->is_preemptible()));
(A valid question is: what is the purpose of making the undefined symbol
have protected visibility? Indeed nothing as far as I can tell... it
looks like I can work around the problem by tweaking my source code so
that I attach visibility only to the definition, not to declarations.)
Test case attached.
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