On Wed, Jun 18, 2025 at 02:31:06 +0000, shynur . wrote: > ``` > INT_MAX=`echo \`printf '%u' -1\`/2 | bc` > IGNOREEOF=INT_MAX > # Then I typed C-d, bash exited... > ```
You probably meant to type $INT_MAX there, not INT_MAX. You assigned a string to the IGNOREEOF variable, not a number. According to the man page, this means it should use the default value of 10. > ``` > IGNOREEOF=127 > # C-d, C-d, C-d, ... > ``` > > Why doesn’t the first piece of code work as expected? You mean, why didn't it require 10 Ctrl-d's? I have no idea. > In Bash, what exactly is the INT_MAX that I can safely use anywhere? Bash versions 2.05b and higher use 64-bit integers for almost everything, on almost(?) all platforms. This feels like an X-Y problem, though. What are you really trying to do here?
