Hello again.
I am deeply sorry, but i have one more difficulty that i fail to
explain to myself. It *could* (small, very small case) be that
this time the incorrectness really is on the side of bash.
This script (do not care for the commented, they are great)
a() {
echo $#,1="$1"/$1,2="$2"/$2,3="$3"/$3,4="$4"
echo $#,'*'="$*"/$*,
}
set -- '' 'a' ''
#IFS=\ ; echo "$*"$* $*; a "$*"$* $*;unset IFS
#IFS= ; echo "$*"$* $*; a "$*"$* $*;unset IFS
IFS=:; echo "$*"$* $*; a "$*"$* $*;unset IFS
outputs
:a: a a
4,1=:a:/ a ,2=a/a,3=/,4=a
4,*=:a::a::a/ a a a,
I have a problem ^ with this space character of bash.
My MUA outputs
4,*=:a::a::a/ a a a,$
instead for this case. I find this logical since before the
resplit we have ":a:" + "a" + "" + "a", and the trailing ":" in
the first only delimits the field of "a", so the next field will
not join, causing the echo(1) argument to be separated by a space
character. But no other space i see.
Thanks, and a good night from Germany i wish,
--steffen
|
|Der Kragenbaer, The moon bear,
|der holt sich munter he cheerfully and one by one
|einen nach dem anderen runter wa.ks himself off
|(By Robert Gernhardt)
