Re: Logical expression works does not work as expected

[Lawrence Velázquez]

On Fri, Dec 27, 2024, at 6:47 PM, Greg Wooledge wrote:
> You might have been raised on some other language where the && and ||
> operators have different precedence.  In the shell language, they have
> the same precedence.

However, the && and || arithmetic operators do have C-like precedence.

        $ echo "$((1 && 1 || 0 && 0))"
        1
        $ echo "$(( ((1 && 1) || 0) && 0 ))"
        0

So be aware of context.

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vq