in the printf to stdout
a final printf \\n is missing
greets
On Tuesday, September 17, 2024, alex xmb sw ratchev <fxmb...@gmail.com>
wrote:
> savedifs=${IFS@A} savedifs=${savedifs:- unset -v IFS }
> str=1,2,3 IFS=, arr=( $str ) joined=${arr[*]}
> eval "$savedifs"
>
> alternative middleline
>
> sep=, str=1$sep2$sep3 IFS=$sep arr=( $str ) joined=${arr[*]}
>
> ( at var=assignment , quotes dont matter , excepts to bind spaced code
> together
> as cmd or cmd args , or array=( here element ) , use quotes around the
> args , eg "$cmd" "$arg" "${argarr[@]}" ; arr=( "$var" "${vararr[@]}" )
> )
>
> to join via first of IFS , as one-string , ${arr[*]}
> to join the elements as args , "${arr[@]}"
> to do this via printf , two cmds are needed ( there are serval approaches )
> one is cutting runaway ,
> {
> printf -v joined2 %s, "${arr[@]}"
> joined2=${joined2%,}
> }
>
> with printf only , and to stdout
> {
> printf %s "$arr"
> printf "$sep%s" "${arr[@]:1}"
> # -- same as ( second printf )
> # printf ,%s "${arr[@]:1}"
> }
>
> there is alternatively an inline way to split strings containing quotes
> and backslashes
> eg {
> str="1" "2" "3"'
> declare -a "split=( $str )"
> }
>
> greets
>
> On Tuesday, September 17, 2024, William Park <opengeome...@yahoo.ca>
> wrote:
>
>> Hi all,
>>
>> Is there fast way of splitting and joining of strings in the recent Bash
>> versions?
>>
>> For splitting, I'm aware of
>> old="a,b,c"
>> IFS=, read -a arr <<< "$old"
>>
>> For joining,
>> new=$(IFS=,; echo "${arr[*]}")
>> or
>> new=$(IFS=,; echo "$*")
>>
>>
>>
