Date: Tue, 27 Aug 2024 22:02:34 +0200
From: Steffen Nurpmeso <[email protected]>
Message-ID: <20240827200234.95X76_wN@steffen%sdaoden.eu>
| Any character in IFS delimits a field, adjacent IFS whitespace
| characters are then ignored.
Not quite. Any sequence of any amount of IFS whitespace, and no
more than one other IFS character delimits a field.
| To the contrary i would now say that with a non-default non-empty
| $IFS only IFS characters that are not also IFS whitespace create
| empty fields.
The preconditions there are irrelevant.
Only IFS chars that are not IFS whitespace create empty fields.
Where IFS is empty, there are no IFS chars, hence nothing delimits
a field. When IFS is unset (default case) it consists of $' \t\n'
(there is no difference whatever, for field splitting, or "$*" for
that matter) between an unset IFS and IFS=$' \t\n'
| |You have to look at the definition of IFS whitespace.
| Already forgotten at that point.
Unfortunately, when reading the standard, you cannot forget a
single word of it. Everything (normative) applies.
kre
