Date: Thu, 14 Mar 2024 09:53:37 -0400
From: Greg Wooledge <[email protected]>
Message-ID: <[email protected]>
| I don't quite understand what this is saying.
It was a weird attempt to explain the behaviour bel9w
| Do the variables have different names, or the same name?
Depends which vars you mean but definitely not a nameref pointing
at itself.
Consider this script (/tmp/s)
f() {
local v=1;
printf 'in f v=%s\n' "$v"
local -n n=v
printf 'in f v=%s n=%s\n' "$v" "$n"
g
printf 'in f v=%s n=%s\n' "$v" "$n"
}
g() {
local v=2
printf 'in g v=%s\n' "$v"
n=3
printf 'in g v=%s n=%s\n' "$v" "$n"
}
f
Then running it (bash /tmp/s) produces
in f v=1
in f v=1 n=1
in g v=2
in g v=2 n=2
in f v=3 n=3
Some people do not understand how that works, believing
that n should always refer to the v in f, rather than the
v in g.
So 'the variables have the same names' are the v in f and v in g
(if those were different there would be no confusion), the nameref
var name is different.
kre
ps: I'm not sure how to explain what happens there either,
looks broken and useless to me.
