On 2/7/24 1:48 AM, Grisha Levit wrote:
If given both the -a and -A flags and an existing scalar variable, declare will assign both attributes to the variable:$ V=X; declare -Aa V; echo $? 0 $ echo ${V@a} aA $ (declare -p V) Segmentation fault: 11
For the time being, we'll make this an error instead of `last one wins'.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU c...@case.edu http://tiswww.cwru.edu/~chet/
