On Tue, Jun 27, 2023 at 12:29 AM n952162 <n952...@web.de> wrote:
> Is this correct?
>
> declare -A l1
>
> l1=([a]=b [c]=d)
> echo ${!l1[@]}
>
> l1=($(echo [a]=b [c]=d))
> echo ${!l1[@]}
>
> $ bash t4
> c a
> [a]=b [c]=d
>
> If so, why? And how can I assign a list of members to an associative
> array?
>
What is t4? Is that a script that contains the lines above?
Your first assignment is a way to assign a list of members to an
associative array. Your second assignment creates a single element with the
index "[a]=b [c]=d" which has a null value.
If you want to see the structure (keys and values) of an array or see the
values of any variable, use declare -p for the most clarity.
$ declare -A l1
$ l1=([a]=b [c]=d). # assignment of a list of keys and values
$ declare -p l1
declare -A l1=([c]="d" [a]="b" )
$ l1=($(echo [a]=b [c]=d)). # not what you want
$ declare -p l1
declare -A l1=(["[a]=b [c]=d"]="" )
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