Re: `declare -f' does not output the "function" keyword when required

[Chet Ramey]

On 12/3/22 6:05 AM, Emanuele Torre wrote:

In Bash, it is possible to define functions that look like assignment
words using the function keyword:

     function a=2 { printf hi\\n ;}

When `declare -f' is used to output all the function definitions, bash
will not output that function definition with the "function" keyword,
generating invalid code:

Thanks for the report.

--
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    c...@case.edu    http://tiswww.cwru.edu/~chet/