On Sat, Aug 13, 2022 at 06:51:04AM +0700, Budi wrote: > It doesn't work means no use on set -x, no value is shown
set -x shows the command being executed, with arguments expanded. unicorn:~$ cat foo #!/bin/bash set -x a=5 b=7 c=$((a * b)) echo "$c" unicorn:~$ ./foo + a=5 + b=7 + c=35 + echo 35 35 In this case, $((a * b)) was expanded to 35 before executing the variable assignment, so that's what set -x shows. Similarly, "$c" was expanded to 35, so set -x shows that as well. What *exactly* were you expecting? We're all being forced to guess, and it's obnoxious.
