On Jul 09 2022, Steffen Nurpmeso wrote: > $ bash -c 'I=3; echo "$((1?(I*=I):I+=I))";echo $I'
The third operand of ?: cannot contain an assignment expression, thus, like in C, this is parsed as `(1?(I*=I):I)+=I'. -- Andreas Schwab, SUSE Labs, sch...@suse.de GPG Key fingerprint = 0196 BAD8 1CE9 1970 F4BE 1748 E4D4 88E3 0EEA B9D7 "And now for something completely different."
