Robert Elz <[email protected]> writes: > Note particularly that there is no operator precedence between > && and || - they are the same (unlike in C for example)
Reading your message, I believe that the rule can be stated as follows,
and I'd thank you to check it: && and || have the same precedence, and
they both "associate left". So for example
x && yy || zz
is equivalent (as a control structure) to
{ x && yy ;} || zz
Dale
