On Wed, 27 Oct 2021 21:09:29 +0200 Toralf Förster <toralf.foers...@gmx.de> wrote:
> Hi, > > expected: > $ i=0; ((i = i + 1)); echo $? > 0 > > expected: > $ i=0; ((++i)); echo $? > 0 This makes use of a pre-increment operator. The evaluated number is 1. > > unexpected: > $ i=0; ((i++)); echo $? > 1 This makes use of a post-increment operator. The evaluated number is 0. > > i is always set to 0, the result is always non-zero, but the return code > differs. This is to be expected. It works the same way as in other languages, such as C. You should use the operator that reflects your intent. -- Kerin Millar
