Re: is it a bug that \e's dont get escaped in declare -p output

[Léa Gris]

Le 17/03/2021 à 21:13, Alex fxmbsw7 Ratchev écrivait :

hm at least now we know array declare -p formatting would work in
workarounds, good to .. :)

Instead of:

var=$'1\e[G\e[K2' ; declare -p var

do:

var=$'1\e[G\e[K2' ; printf 'declare -- %s\n' "${var@A}"

And if you want a human readable dumpvars, then code it.

Here it is:

#!/usr/bin/env bash

dump_vars () {
  local ___varname
  for ___varname; do
    local ___varflags=${!___varname@a}
    ___varflags=${___varflags:--}
    if [[ "$___varflags" =~ [Aa] ]]; then
      declare -p "$___varname"
    else

    fi
  done
}

escapestring=$'1\e[G\e[K2'
escapearray=($'new \n line' $'and \e esc')

declare -i intvar=42
declare -ai intarray=(-42 666 555)
declare -Ai intassoc=([foo]=123 [$'1\e[G\e[K2']=456 [bar]=789)

dump_vars escapestring escapearray assocarray intvar intarray intassoc

Output:

printf 'declare -%s %s=%q\n' "$___varflags" "$___varname" "${!___varname}" declare -A assocarray=([$'1\e[G\e[K2']=$'and \e esc' [$'new \n line']=$'1\e[G\e[K2')

declare -- escapestring=$'1\E[G\E[K2'
declare -a escapearray=([0]=$'new \n line' [1]=$'and \E esc')
declare -A assocarray=([$'1\E[G\E[K2']=$'and \E esc' [$'new \n 
line']=$'1\E[G\E[K2' )
declare -i intvar=42
declare -ai intarray=([0]="-42" [1]="666" [2]="555")
declare -Ai intassoc=([$'1\E[G\E[K2']="456" [foo]="123" [bar]="789" )
declare -i nameref=42

--
Léa Gris

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