On Wed, Oct 21, 2020 at 04:48:39PM +0200, r...@beelaertsict.nl wrote:
> #!/bin/bash
> # test error in while clause
> #
> set -x
> up () {
> i=$(($i+1))
> [ $i -eq 5 ] && j=$(($j+1)) && i=0
> }> while [ $i -ne 4 -o $j -ne 2 ] > do > if [ $i -eq 3 ] > then > up && continue If $i is 3, you call up. up increments i, so $i is now 4. Then it runs [ $i -eq 5 ] which is false, so the function returns false. Therefore, continue is never executed here.
