On 06/07/2020 12:50 pm, Greg Wooledge wrote:
On Fri, Jul 03, 2020 at 07:00:54PM +0100, Chris Elvidge wrote:
I've used 'return $((!$#))' and 'return $[!$#]' to return an error if no
parameters given to function.
The problem with this is that it *always* returns from the function,
even when paramters are given.
If you actually want to do what you said, you need a conditional check
of some kind, either "if" or "||".
(($#)) || return 1
would be my preference, if you really do not want to give any kind of
error message to indicate *why* you are returning with a failure code.
If you want to add an error message, then I would go with "if".
if ((! $#)); then
echo "usage: myfunc arg1 ..." >&2
return 1
fi
This is a function only for me. The return comes after a help section.
[[ $# -eq 0 || "$1" =~ -h ]] && etc. No error message required, just an
indication.
Thanks for the pointers.
--
Chris Elvidge
England
