Hi, please see the following script:
> #!/bin/bash > shopt -s failglob > if [[ $? -ne 0 ]]; then > echo 'shopt failed' > exit 1 > fi > > # Let's view current options just to be sure > shopt -p > > # The following glob should fail because /foo/bar does not exist ... > # Due to 'failglob' option, bash should stop here > echo /foo/bar/* > > # This code should never run if previous glob failed > echo Still alive Is the assumption true that "Still alive" should *never* be printed when "/foo/bar" does not exist? With bash 4.4-5 (aka 4.4.12(1)) on Debian Stretch and 4.4.23(1) on Gentoo, "Still alive" will be printed. When you add "set -e" to the beginning, execution will stop immediately after the failing glob, i.e. no "Still alive" will be printed. However, see the following interesting difference between semicolons and newlines: > $ echo "shopt -s failglob; echo /foo/bar/*; echo alive; " | bash > bash: line 1: no match: /foo/bar/* > $ echo "shopt -s failglob; echo /foo/bar/*; echo alive; " | sed 's:; :\n:g' | > bash > bash: line 2: no match: /foo/bar/* > alive > $ echo "set -e; shopt -s failglob; echo /foo/bar/*; echo alive; " | sed 's:; > :\n:g' | bash > bash: line 3: no match: /foo/bar/* > $ -- Regards, Thomas Deutschmann / Gentoo Linux Developer C4DD 695F A713 8F24 2AA1 5638 5849 7EE5 1D5D 74A5
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