On Tue, Jul 17, 2018 at 05:47:20PM -0400, Grisha Levit wrote:
> At global scope this works as expected:
>
> $ declare -n ref=var; declare -a ref=(X); declare -p ref var
> declare -n ref="var"
> declare -a var=([0]="X")
>
> But in a function, we end up with the nameref variable having both the
> `a' and `n' attributes and nothing in the target:
>
> $ f() { declare -n ref=var; declare ref=(X); declare -p ref var; }; f
> declare -an ref=([0]="X")
> -bash: declare: var: not found
FYI that one is already fixed in 5.0-alpha:
wooledg:~$ declare -n ref=var; declare -a ref=(X); declare -p ref var
declare -n ref="var"
declare -a var=([0]="X")
wooledg:~$ f() { declare -n ref=var; declare ref=(X); declare -p ref var; }; f
declare -an ref=([0]="X")
declare -a var=([0]="X")
Or at least partly fixed. *shrug*
