On 7/10/18 4:57 PM, Isaac Marcos wrote:
> Chet Ramey (<[email protected] <mailto:[email protected]>>) wrote:
>
> On 7/10/18 2:48 PM, Isaac Marcos wrote:
> > That is not an integer constant. Integer constants don't begin
> with `-'.
>
>
> That makes negative numbers invalid.
You need to look at the difference between constants and operators. This is
what allows you to write $(( -a )), for instance.
> Because of the difference between an operator and a constant. Unary plus
> and minus have a higher precedence than arithmetic operators. So if you
> expand the `a' to an expression, which is what happens, the expression
> consists of an operator (+ or -) and a constant, and that expression has
> a higher precedence than the +. You might think about why using `$a' in
> place of the `a' would not work all the time.
>
>
>
> I don't care. All other shells do this correctly. It makes you the only one
> wrong.
"All other shells" is kind of a broad statement.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU [email protected] http://tiswww.cwru.edu/~chet/
