On 4/2/18 5:16 PM, PRussell wrote:
> Section 6.5 Shell Arithmetic says,
>
> "Within an expression, shell variables may also be referenced by name without
> using the parameter expansion syntax. A shell variable that is null or unset
> evaluates to 0 when referenced by name without using the parameter expansion
> syntax." - http://www.gnu.org/software/bash/manual/bash.html#Shell-Arithmetic
>
> The above tells us what happens to an unset variable if not using parameter
> expansion.
>
> But if a shell variable uses parameter expansion and is null or unset, what
> does it evaluate to inside (()) syntax?
Since ((...)) is equivalent to let "...", as noted in the description of
`((' in the man page and info doc, it expands to the same thing that it
would when you perform a double-quoted word expansion. If you expand a
shell variable that's null or unset, you get the usual: it disappears.
> The problem is what is happening with 3B and 4B. I tested on bash 4.3.11 and
> bash 4.4.19 and got a slightly different error message.
>
> Bash version 4.3.11:
>
> ./tt: line 18: var1: var1 == : syntax error: operand expected (error token
> is "== ")
>
> Bash version 4.4.19 (???? was garabage):
>
> ./tt: line 18: ????: var1 == : syntax error: operand expected (error token
> is "== ")
I don't get this. I get `((' as the command name in the error message for
both bash-4.3.46 and bash-4.4.19:
./x18: line 1: ((: var1 == : syntax error: operand expected (error token
is "== ")
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU c...@case.edu http://tiswww.cwru.edu/~chet/
