See following example:
[STEP 100] # echo $BASH_VERSION
4.4.12(2)-release
[STEP 101] # v=abc
[STEP 102] # printf '%q\n' $v
abc
[STEP 103] # printf '%s\n' "${v@Q}"
'abc'
[STEP 104] #
Is it possible to not quote the result since there's no special chars in
the string? I would expect ${var@Q} to produce more concise result compared
to `printf %q' since it's the new syntax. :)
-clark
