On 12/30/16 11:07 PM, Grisha Levit wrote: > On Fri, Dec 30, 2016 at 11:03 PM, PePa <peterke...@passchier.net > <mailto:peterke...@passchier.net>> wrote: > > r=23; echo $r; echo -e "r=bc\necho $r" |bash > > You need to escape the |$| in the second echo statement so that |$r| is not > evaluated to |23| before being echoed.
The easiest way to see what bash gets on its standard input is to replace `bash' in the pipeline with `cat'. -- ``The lyf so short, the craft so long to lerne.'' - Chaucer ``Ars longa, vita brevis'' - Hippocrates Chet Ramey, UTech, CWRU c...@case.edu http://cnswww.cns.cwru.edu/~chet/