Re: possible in bash?: filter stderr of a prog & send filtered-output out on stderr leaving stdout untouched

[L A Walsh]

Andreas Schwab wrote:

{ $prog 2>&1 >&3 | grep -v "$RE_filt" >&2; } 3>&1

Andreas.

Closer to my last failed case:

   ( echo -n >&3 $($prog >&3 2>&1 | grep -Pv "$re" >&2 ) ) 3>&1

Had tried not putting $prog in $(), but bash didn't like the parens...

At that point figured it was probably solved and asked onlist...

Thanks for the added input!

-l