On 07/19/2016 09:45 PM, Chet Ramey wrote: > On 7/19/16 7:15 PM, Dan Douglas wrote: >> Hi, I could reproduce this in all bash versions. >> >> bash -c 'set -x; until continue; do :; done; echo test1'; echo test2 >> + continue >> test2 >> >> I'm not actually sure whether this is supposed to work at all. Almost >> all shells do something strange when given continue in the first >> compound-list. E.g. ksh93 does like bash and exits, and zsh breaks >> out of the loop. > > It should probably print `test1'
That's what I figured. Playing around with this test the current bash
continues an outer loop if levels=1 while the "normal" ones (dash/mksh)
do so at levels=2. I suppose technically a script that before would
have continued the n+1th nested loop will now be off by one. (Not too
likely such a script exists or they would have noticed this.)
$ { bash /dev/fd/9; echo; } 9<<\EOF
set -x; n=-1 levels=1
let 1 2>/dev/null || let() { IFS=, command eval test '$(($*))' -ne 0; }
until
echo 1
let n+=1 && break
do
until
echo 2;
continue "$levels"
do :
done
echo 3
done
EOF
+ n=-1
+ levels=1
+ let 1
+ echo 1
1
+ let n+=1
+ echo 2
2
+ continue 1
+ echo 1
1
+ let n+=1
+ break
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