On Fri, Jun 10, 2016 at 02:53:23PM +0200, psko...@gmail.com wrote: > declare var > declare -a ary > declare -A asoc > > var=1 > ary=(1) > asoc[a]=1 > > for a in var ary asoc; do > printf '%s\t' "$a" > if test -v "$a"; then ...
With arrays, remember that "foo" is the same as "foo[0]" in all contexts. When you do your test -v on an array's name, you are really doing it on the array element with index [0]. imadev:~$ unset a imadev:~$ declare -A a imadev:~$ a[foo]=bar imadev:~$ test -v a; echo $? 1 imadev:~$ test -v 'a[foo]'; echo $? 0 imadev:~$ test -v 'a[qz]'; echo $? 1 imadev:~$ unset a imadev:~$ a[17]=foo imadev:~$ test -v a; echo $? 1 imadev:~$ test -v 'a[17]'; echo $? 0 imadev:~$ test -v 'a[1]'; echo $? 1 Your script gave you a slightly misleading result because with your indexed array, element [0] existed: you initialized the array so that element [0] had the value 1. But your associative array was initialized so that only element [a] existed.
