On Wed, Oct 28, 2015 at 11:35:42AM +0100, Oskar Maier wrote:
> http://stackoverflow.com/questions/33371309/change-in-behaviour-of-declare-local-from-bash-4-2-to-4-3
Here is the text:
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I've recently updated my system and got a new bash version. Since then I've
encountered some nasty behaviour of my bash scripts, which I finally managed to
track down to a new behaviour of bash's declare / local commands.
Considering the following minimal working example:
#!/bin/bash
function printarray1 () {
local -a arr=("${!1}")
echo "${arr[@]}" # printing the complete array
echo "${arr[9]}" # just to check if it is really recognized as an integer
indexed array
}
function printarray2 () {
local arr=("${!1}")
echo "${arr[@]}" # printing the complete array
echo "${arr[9]}" # just to check if it is really recognized as an integer
indexed array
}
arr=("01" "02" "03" "04" "05" "06" "07" "08" "09" "10")
echo "Declaration as indexed array:"
printarray1 arr[@]
echo "Undefined declaration:"
printarray2 arr[@]
On GNU bash, version 4.2.25(1)-release (x86_64-pc-linux-gnu) this results in
Declaration as indexed array:
01 02 03 04 05 06 07 08 09 10
10
Undefined declaration:
01 02 03 04 05 06 07 08 09 10
10
while the newer GNU bash, version 4.3.11(1)-release (x86_64-pc-linux-gnu)
version returns
Declaration as indexed array:
Undefined declaration:
01 02 03 04 05 06 07 08 09 10
10
Note that the behaviour is the same when I use "declare" instead of "local".
I could not find anything about a change of the declare options in Bash 4.3.
The help (help declare) is equal in both versions for all relevant information.
I've even stumbled upon the claim that "All variables can be used as arrays
without explicit definition." (see Why are "declare -f" and "declare -a" needed
in bash scripts?).
Can anyone explain this behaviour? Is it a new feature? Or simply a bug? Has
the passing of arrays to functions been restricted? To me it's pretty scary
when the bash behaviour suddenly changes from version to version.
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