On Tue, Mar 31, 2015 at 06:04:53PM +0300, Filimonov Vadim wrote: > filimonov@filimonov:~/bashbug/bash-4.3$ read -u63 LINE <(echo "*") > bash: read: `/dev/fd/63': not a valid identifier
You are missing a < sign here. You probably wanted: read LINE < <(echo "*") It is not safe to assume that the <() will produce a reference to file descriptor 63. On many platforms, it won't even use /dev/fd/ at all, but will instead use a named pipe. Your command expands to read -u63 LINE /dev/fd/63 Which produces the error message, as it tries to treat /dev/fd/63 as a variable name to assign into. However, before it runs into that error, it has already read a "*" character from file descriptor 63 (since you told it to do that with -u63). And that * character is now in the variable named LINE. > ... ;echo $LINE > ABOUT-NLS aclocal.m4 alias.c alias.h alias.o array.c arrayfunc.c arrayfunc.h > arrayfunc.o array.h array.o assoc.c assoc.h assoc.o AUTHORS bash bashansi.h > bashbug bashhist.c bashhist.h bashhist.o bashintl.h bashjmp You always want echo "$LINE" and *never* echo $LINE. http://mywiki.wooledge.org/BashPitfalls#pf14 The * from $LINE was expanded because you failed to quote properly.
