Hello.
I often use "set -eu" to make my scripts more robust by exiting when
there are errors.
But one of my scripts just kept on running after failures. I found out
that the keyword "local" does not obey it. Here is a script to
reproduce the problem:
#!/bin/bash
set -eu
failure() {
echo "going to fail"
false
}
cmd-subst-failure-with-local() {
echo "calling failure without failing because of local"
local FAILUREOUT=$(failure)
echo "Bug: set -eu wasn't effective: failure output was '$FAILUREOUT'"
}
cmd-subst-failure-without-local() {
echo "calling failure so it fails (without local)"
FAILUREOUT=$(failure)
# here set -eu works so we will fail instead of getting here
echo "Internal error, set -eu didn't work even without local"
}
cmd-subst-failure-with-local
cmd-subst-failure-without-local
