On 9/2/14, 2:59 PM, jim.av...@gmail.com wrote:
> Bash Version: 4.3
> Patch Level: 0
> Release Status: release
>
> Description:
>
> The "source" (or ".") command, if invoked from within a function,
> creates a call frame, setting $FUNCNAME[0] to "source" and
> $BASH_SOURCE[1] and $BASH_LINENO[1] to the location of the "source"
> statement.
>
> However this does not occur if the "source" statement occurs in
> mainline code, i.e. outside of any function.
This is true. The FUNCNAME variable is not visible outside functions, so
the assignment of `source' to FUNCNAME, which was done primarily for the
bash debugger's convenience, doesn't have any effect when outside a
function.
>
> This means that code in "sourced" files can not reliably
> display the location of their call, i.e., the location of
> the "source" (or ".") statement which invoked them.
But this is not. If you want to see where the sourced file was invoked,
use ${BASH_SOURCE[1]}:${BASH_LINENO} or the `caller' builtin.
Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU c...@case.edu http://cnswww.cns.cwru.edu/~chet/
