In info -f bash -n 'Invoking Bash'
we find: > `-c' > Read and execute commands from the first non-option ARGUMENT after > processing the options, then exit. Any remaining arguments are > assigned to the positional parameters, starting with `$0'. $0 is generally *not* considered as a positional parameter. Both POSIX (http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_05_01) and "info -f bash -n 'Positional Parameters'" have: > A positional parameter is a parameter denoted by the decimal > value represented by one or more digits, other than the single > digit 0 explicitetly excluding $0. That seems to be causing some confusion https://unix.stackexchange.com/questions/152391 Maybe a better wording would be: > `-c' > Read and execute commands from the first non-option ARGUMENT after > processing the options, then exit. The first argument > after that is assigned to $0 which is used in error > messages for instance (in the abscence of arguments, $0 > is assigned to the argv[0] that the interpreter received > (usually bash or sh)), and the following arguments are > assigned to the positional parameters. The note of $0 being used for error messages would also be useful as we see people using a place-holder like _ or -- there causing more confusion. See for instance: http://mywiki.wooledge.org/BashFAQ/012 -- Stephane
