Tim Friske <m...@tifr.de> writes: > my assumption was that Bash's "printf" builtin implicitly defines a local > variable when used inside a function like so:
Why? A simple assignment doesn't either, and that's what printf does in the end. Andreas. -- Andreas Schwab, sch...@linux-m68k.org GPG Key fingerprint = 58CA 54C7 6D53 942B 1756 01D3 44D5 214B 8276 4ED5 "And now for something completely different."
