I'm a newcomer to the bug-bash mailing list; I apologize in advance if this isn't the appropriate forum for this type of question. I suspect this isn't a bug, but I'm very confused about the purpose of the -C option for the compgen builtin. As the warning message states, it's not working as I expected. I posted a question about this to unix.stackexchange.com. Here is a link to the post:
http://unix.stackexchange.com/questions/117987/compgen-warning-c-option-not-working-as-i-expected/ And here is what I posted: What is the correct way to use the compgen -C option? I'm trying to learn about Bash programmable completion, and in particular the compgen builtin function. I'm experimenting with the different compgen command-line options, and I don't understand how the -C flag is supposed to work. From the GNU Bash Reference Manual: -C command command is executed in a subshell environment, and its output is used as the possible completions. Based on this, I expect something like the following to work: $ compgen -C 'echo "first_option second_option"' f first_option But instead, I get this: $ compgen -C 'echo "first_option second_option"' f -bash: compgen: warning: -C option may not work as you expect first_option second_option f I've tried this with Bash version 4.2.45 on OS X 10.7 and with Bash version 4.2.25 on Ubuntu 12.04, and in both cases I get the same error: -bash: compgen: warning: -C option may not work as you expect How *should* I expect the -C option to work? What is it's purpose? Where is it's use documented? Thanks in advanced.
