as greg say this is the wrong list you need to report this to
" Vim syntax file
" Language: shell (sh) Korn shell (ksh) bash (sh)
" Maintainer: Dr. Charles E. Campbell, Jr.
<ndroch...@pcampbellafamily.mbiz>
" Previous Maintainer: Lennart Schultz <lennart.schu...@ecmwf.int>
" Last Change: Dec 09, 2011
" Version: 121
" URL:
[1]http://mysite.verizon.net/astronaut/vim/index.html#vimlinks_syntax
the file that does this is /usr/share/vim/vim73/syntax/sh.vim in an
ubuntu system.
and this is probably a simpler example to work with
#!/bin/bash
while true; do
while true; do
done
until true; do
done
done
until true; do
while true; do
done
until true; do
done
done
cheers
Gesendet: Dienstag, 04. Juni 2013 um 22:15 Uhr
Von: "Greg Wooledge" <wool...@eeg.ccf.org>
An: kartik...@gmail.com
Cc: bug-bash@gnu.org, b...@packages.debian.org
Betreff: Re: nested while loop doesn't work
On Tue, Jun 04, 2013 at 04:39:31PM +0530, kartik...@gmail.com wrote:
> Description:
> A while inside a while loop (nested while) doesnt work and also the
vim /gvim doesnt highlight the second while loop
For issues with the vim/gvim highlighting, you'd need to report the
problem in vim, not in bash.
> example code is given
>
> while [ "ka" = $name ]
> do
> echo "nothing\n"
> while [ "ka" = $name ] //this while is not highlighted
> do
> echo "everything\n"
> done
> done
You have a quoting mistake here. "$name" should be quoted, or this will
fail if the variable contains multiple words separate by spaces.
imadev:~$ name="first last"
imadev:~$ [ "ka" = $name ]
bash-4.3: [: too many arguments
This code should work:
while [ "ka" = "$name" ]
do
printf "nothing\n\n"
while [ "ka" = "$name" ]
do
printf "everything\n\n"
done
done
(It goes into an infinite loop when name=ka, but presumably that's what
you wanted.)
References
1.
https://3c.web.de/mail/client/dereferrer?redirectUrl=http%3A%2F%2Fmysite.verizon.net%2Fastronaut%2Fvim%2Findex.html%23vimlinks_syntax&selection=tfol11a7bad28b16cbfe
