On Thu, Apr 18, 2013 at 11:59:40AM +0200, and...@coolbox.se wrote:
> The ARITHMETIC EVALUATION section of the man page claims equivalence with C
> for all the operators, but in reality bash does not perform short circuit
> evaluation, which implies that the logical operators do NOT produce the same
> results as in C.
You missed this part, under EXPANSION:
Expansion is performed on the command line after it has been split
into words. There are seven kinds of expansion performed: brace
expansion, tilde expansion, parameter and variable expansion, command
substitution, arithmetic expansion, word splitting, and pathname
expansion.
The order of expansions is: brace expansion, tilde expansion,
parameter, variable and arithmetic expansion and command substitution
(done in a left-to-right fashion), word splitting, and pathname
expansion.
It's not clear from this part of the documentation how bash handles
a command substitution nested inside an arithmetic expansion, but you've
experimentally demonstrated that the nested substitution is performed
first.
Once the nested substitution has been done, short circuit evaluation
DOES take effect. Here's a demonstration of short circuit without
the nested substitution causing confusion:
imadev:~$ echo $((1/0))
bash: 1/0: division by 0 (error token is "0")
imadev:~$ echo $((0 && 1/0))
0
