Not sure if this is the correct forum for this, as I am very uncertain that it is a bash-bug and am more inclined to believe it is some odd interpretation causing my code to go hay-wire in this instance. So if I should move this to another discussion location, I'm fine with that -- I'm just trying to figure out why something of the form
include lib/Util/Needroot.shh where include is a function the name of a file in my path (or an alias to define the function)... /home/law/bin/recycle_space: line 7: lib/Util/needroot.shh: division by 0 (error token is "/needroot.shh") If I try: changing the path to: Util/needroot.shh I get: /home/law/bin/recycle_space: line 7: Util/needroot.shh: syntax error: invalid arithmetic operator (error token is ".shh") If I add double quotes around the pathname (as I didn't think they should be needed in this case), it makes no difference. I get the same message as in the first case (div by 0) It might be thought that the issue is complicated by the fact that needroot.shh will re-execute the original script with 'sudo' if it is run by a non-root user, but running the script (recycle_space) AS root (when the 'needroot.shh' _doesn't_ re-execute itself, also results in the same error. Are there any 'odd circumstances' where an argument to a function is automatically eval'd as an integer expression instead of just being passed as a string? This has been a problem for several months, just that it IS work-around able and the multiple attempts at re-following the execution flow haven't yielded anything new -- just more cryptic symptoms...(like the line the 'include is on, isn't even on line 7, it's on line 14...minor things like that... ;-/). Ideas?
